document.write( "Question 1184034: If x is not equal to 0, then\r
\n" ); document.write( "\n" ); document.write( "x-2y/2y-x + 2y-x/x-2y\r
\n" ); document.write( "\n" ); document.write( "The correct answer is -2 but I don't know how that the answer.
\n" ); document.write( "

Algebra.Com's Answer #814572 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "Curiously, the expression you show is indeed equal to -2; and the expression you undoubtedly INTENDED to show is also equal to -2.

\n" ); document.write( "Here is the expression you show: \"x-2y/2y-x + 2y-x/x-2y\"

\n" ); document.write( "\"x-2y%2F2y-x+%2B+2y-x%2Fx-2y+=+%28x-1-x%29%2B%282y-1-2y%29+=+%28-1%29%2B%28-1%29+=+-2\"

\n" ); document.write( "Here, on the other hand, is the expression you most probably meant: \"(x-2y)/(2y-x)+(2y-x)/(x-2y)\"

\n" ); document.write( "

\n" ); document.write( "If you are working problems like this, your math knowledge should be great enough to know that proper use of parentheses is important...!

\n" ); document.write( "
\n" ); document.write( "
\n" );