document.write( "Question 1184034: If x is not equal to 0, then\r
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document.write( "x-2y/2y-x + 2y-x/x-2y\r
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document.write( "The correct answer is -2 but I don't know how that the answer. \n" );
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Algebra.Com's Answer #814572 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Curiously, the expression you show is indeed equal to -2; and the expression you undoubtedly INTENDED to show is also equal to -2. \n" ); document.write( "Here is the expression you show: \"x-2y/2y-x + 2y-x/x-2y\" \n" ); document.write( " \n" ); document.write( "Here, on the other hand, is the expression you most probably meant: \"(x-2y)/(2y-x)+(2y-x)/(x-2y)\" \n" ); document.write( " \n" ); document.write( "If you are working problems like this, your math knowledge should be great enough to know that proper use of parentheses is important...! \n" ); document.write( " \n" ); document.write( " |