document.write( "Question 1184034: If x is not equal to 0, then\r
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document.write( "x-2y/2y-x + 2y-x/x-2y\r
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document.write( "The correct answer is -2 but I don't know how that the answer. \n" );
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Algebra.Com's Answer #814562 by Theo(13342)![]() ![]() You can put this solution on YOUR website! it looks like the correct answer really is -2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the expression is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-2y) / (2y-x) + (2y-x) / (x-2y)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-2y) is equal to -1 * (2y-x) \n" ); document.write( "(2y-x) is equal to -1 * (x-2y)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the expression becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-(2y-x)/(2y-x) + -(x-2y)/(x-2y) which is equal to:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-1 + -1 which is equal to:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |