document.write( "Question 1184018: Susan and Jenny run a 200 m race which Susan wins by 10 m. Jenny suggests that they run
\n" ); document.write( "another race, with Susan starting 10 m behind the starting line. Assuming they run at the same
\n" ); document.write( "speeds as in the first race, what is the outcome of the race? \n" ); document.write( "

Algebra.Com's Answer #814557 by MathTherapy(10552) $\"\"$ $\"About$

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\n" ); document.write( "Susan and Jenny run a 200 m race which Susan wins by 10 m. Jenny suggests that they run
\n" ); document.write( "another race, with Susan starting 10 m behind the starting line. Assuming they run at the same
\n" ); document.write( "speeds as in the first race, what is the outcome of the race?
\n" ); document.write( "

This TRAVEL problem, just like most of them involves using the travel formula: Distance = Speed * Time\r\n" );
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document.write( "Let Susan’s speed be S\r\n" );
document.write( "Then time Susan took to complete the race = \r\n" );
document.write( "Then, Jenny’s speed, with her time also being  is \r\n" );
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document.write( "If Susan starts 10 m behind the starting line, she’ll have to travel 200 + 10 = 210 m\r\n" );
document.write( "Jenny, however, will travel 200 m\r\n" );
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document.write( "Time Susan takes to travel 210 m: \r\n" );
document.write( "Time Jenny takes to travel 200 m: \r\n" );
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document.write( "Susan’s time: \r\n" );
document.write( "Comparing Susan’s time:  to Jenny’s time: , we see that Susan’s time is less, so Susan will win the race, again!

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