document.write( "Question 1184018: Susan and Jenny run a 200 m race which Susan wins by 10 m. Jenny suggests that they run
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Algebra.Com's Answer #814547 by ikleyn(52781) $\"\"$ $\"About$

You can put this solution on YOUR website!
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document.write( "Let x be the Susan's rate (in meters per second), and let y be the Jenny's rate.\r\n" );
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document.write( "Susan's time is    seconds;  it is equal to  , according to the condition.\r\n" );
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document.write( "So, we have   = ,  or    =  = .   (1)\r\n" );
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document.write( "Next, in the other scenario, Susan's time to complete 210 m run will be    seconds,\r\n" );
document.write( "while the Jenny's time to complete her run of 200 m  will be  .\r\n" );
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document.write( "The problem asks which value is lesser,    or  .\r\n" );
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document.write( "From (1),  we have x = ,  therefore\r\n" );
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document.write( "    Susan's time will be   =  =  =  = .\r\n" );
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document.write( "    Obviously, it is less than the Jenny's time  .\r\n" );
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document.write( "So, the conclusion is:  Susan will win (will be first) in the second scenario run.    ANSWER\r\n" );
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There is even more easy and comprehensive explanation.

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\n" ); document.write( "\n" ); document.write( "        From the given part, Susan runs faster than Jenny.\r
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\n" ); document.write( "\n" ); document.write( "        They run 200 meters (Susan) and 190 meters (Jenny) in the same time.\r
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\n" ); document.write( "\n" ); document.write( "        If we add the same ANY arbitrary distance D (like 10 meters in the problem) to 200 m and 190 m respectively,\r
\n" ); document.write( "\n" ); document.write( "        Susan will cover the new distance of 200 + D meters   QUICKER   than Jenny will cover her distance of 190 + D meters.\r
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