document.write( "Question 1184009: How many quarts of pure antifreeze must be added to 5 quarts of a 30% antifreeze solution to obtain a 50% antifreeze solution \n" ); document.write( "
Algebra.Com's Answer #814539 by ikleyn(52787)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "            In my previous post,  I gave a detailed description of the solution procedure to a  TWIN  problem in word form.\r
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document.write( "The basic equation is\r\n" );
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document.write( "    \"%28x+%2B+0.3%2A5%29%2F%28x%2B5%29\" = 0.5\r\n" );
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document.write( "    x + 0.3*5 = 0.5*(x+5)\r\n" );
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document.write( "    x + 1.5  = 0.5x + 2.5\r\n" );
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document.write( "    x - 0.5x  = 2.5 - 1.5\r\n" );
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document.write( "      0.5x    = 1.0\r\n" );
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document.write( "         x    = \"1.0%2F0.5\" = 2.\r\n" );
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document.write( "ANSWER.  2 quarts of the pure antifreeze must be added.\r\n" );
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document.write( "CHECK.   \"%282+%2B+0.3%2A5%29%2F%285%2B2%29\" = \"3.5%2F7\" = \"1%2F2\" = 0.5 = 50%    ( ! correct concentration ! )\r\n" );
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