document.write( "Question 1184009: How many quarts of pure antifreeze must be added to 5 quarts of a 30% antifreeze solution to obtain a 50% antifreeze solution \n" ); document.write( "
Algebra.Com's Answer #814537 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "A classic formal algebraic solution would go something like this.... \n" ); document.write( "You are mixing 5 quarts that is 30% antifreeze and x quarts that are 100% antifreeze to get (5+x) quarts that is 50% antifreeze: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWER: 2 quarts \n" ); document.write( "An informal method that will give you the answer within 15 seconds if you understand it.... \n" ); document.write( "(1) Look at the three percentages 30, 50, and 100 on a number line and observe/calculate that 50 is 2/7 of the way from 30 to 100. (30 to 100 is a difference of 70; 30 to 50 is a difference of 20; 20/70 = 2/7.) \n" ); document.write( "(2)That means 2/7 of the mixture is the 100% antifreeze that you are adding. \n" ); document.write( "(3) So the 5 quarts you started with is 5/7 of the mixture; that means 2/7 of the mixture is 2 quarts. \n" ); document.write( "ANSWER: 2 quarts \n" ); document.write( " \n" ); document.write( " |