document.write( "Question 1184000: From a full 50 liter container of a 40% conentration of acid, x liters is removed and replaced with 100% acid. \r
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document.write( "- Write the amount of acid in the final mixture as a function of x\r
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document.write( "--Determine the domain and range of the function. \r
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document.write( "Thanks! \n" );
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Algebra.Com's Answer #814517 by Theo(13342)![]() ![]() You can put this solution on YOUR website! yout total amount of solution is 50 liters. \n" ); document.write( "the amount of acid is .4 * 50 = 20 liters. \n" ); document.write( "if you take out x liters, you are taking out .4 * x liters of acid and you are putting back in 1 * x liters of acid. \n" ); document.write( "your net gain is .6 * x liter of acid. \n" ); document.write( "the amount of acid in the final solution is 20 + .6 * x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for example: \n" ); document.write( "assume x = 30 \n" ); document.write( "you take out 30 liters of 40% solution and replace it with 30 liters of 100% solution. \n" ); document.write( "your net gain is 30 liters of 60% solution = 18 liters of acid. \n" ); document.write( "your total acid is now 20 + 18 = 38 liters of acid. \n" ); document.write( "you had 20 liters of acid in the solution. \n" ); document.write( "you lost 30 * .4 = 12 liters of acid. \n" ); document.write( "you added 30 liters of acid. \n" ); document.write( "your total acid is 20 - 12 + 30 = 38 liters. \n" ); document.write( "20 + .6 * 30 = 38\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "formula looks good. \n" ); document.write( "the amount of acid you are left with is equal to 20 + .6 * x.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |