document.write( "Question 1183978: Susan invested a total of $10000 in two accounts. One account pays 4 interest and the other account pays 6% Interest. The total retum from both accounts was $560. \r
\n" ); document.write( "\n" ); document.write( "Answer the following questions. \r
\n" ); document.write( "\n" ); document.write( "How much was invested at 4%?
\n" ); document.write( "How much was invested at 6%?\r
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Algebra.Com's Answer #814504 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "The other tutor showed a good formal algebraic solution using the standard method.

\n" ); document.write( "If a formal algebraic solution is not required, and if the speed of getting an answer is important (as in a timed math competition), then here is a very fast and easy way to solve this problem (and many similar problems) mentally.

\n" ); document.write( "(1) $10000 all invested at 4% would yield $400 interest; all at 6% would yield $600 interest.
\n" ); document.write( "(2) The actual interest $560 is 4/5 of the way from $400 to $600. (Picturing the three numbers 400, 560, and 600 on a number line might help: 400 to 600 is a difference of 200; 400 to 560 is a difference of 160; 160/200 = 4/5.)
\n" ); document.write( "(3) That means 4/5 of the $10000 was invested at the higher rate.

\n" ); document.write( "ANSWER: 4/5 of $10000, or $8000, was invested at 6%; the other $2000 at 4%.

\n" ); document.write( "CHECK: .06(8000)+.04(2000) = 480+80 = 560

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