document.write( "Question 1183978: Susan invested a total of $10000 in two accounts. One account pays 4 interest and the other account pays 6% Interest. The total retum from both accounts was $560. \r
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Algebra.Com's Answer #814501 by ikleyn(52787) $\"\"$ $\"About$

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document.write( "Let x be the amount invested at 6%.\r\n" );
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document.write( "Then the amount invested at 4% is (10000-x) dollars.\r\n" );
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document.write( "The 6% investment generates 0.06x dollars as the annual interest.\r\n" );
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document.write( "The 4% investment generates 0.04*(10000-x) dollars as the annual interest.\r\n" );
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document.write( "The total annual interest is the sum  0.06 + 0.04*(10000-x)  dollars.\r\n" );
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document.write( "It is equal to $560  (given).\r\n" );
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document.write( "So we have this equation for the total annual interest\r\n" );
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document.write( "    0.06x + 0.04*(10000-x) = 560  dollars.\r\n" );
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document.write( "From the equation\r\n" );
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document.write( "    x =   = 8000.\r\n" );
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document.write( "ANSWER.  $8000 invested at 6% and the rest,  10000-8000 = 2000  dollars invested at 4%.\r\n" );
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document.write( "CHECK.  0.06*8000 + 0.04*2000 = 560 dollars, total annual interest.    ! Correct !\r\n" );
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