document.write( "Question 16708: 1.) 3x+y=15
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document.write( " y=3\r
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document.write( "2.)3x-2y=12
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document.write( " -y+9=x \n" );
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Algebra.Com's Answer #8145 by elima(1433)![]() ![]() ![]() You can put this solution on YOUR website! 1.) 3x+y=15 \n" ); document.write( " y=3 \n" ); document.write( "This equation you are just going to plug in the y=3 into the equation; \n" ); document.write( "3x+3=15 \n" ); document.write( "subtract 3 from both sides; \n" ); document.write( "3x+3-3=15-3 \n" ); document.write( "3x=12 \n" ); document.write( "Divide each side by 3; \n" ); document.write( " \n" ); document.write( "x=4 \n" ); document.write( "2.)3x-2y=12 \n" ); document.write( " -y+9=x \n" ); document.write( "This equation your are first going to solve the second equation for y; \n" ); document.write( "-y+9=x \n" ); document.write( "y=-x+9\r \n" ); document.write( "\n" ); document.write( "Now plug that into the other equation for y; \n" ); document.write( "3x-2(-x+9)=12 \n" ); document.write( "3x+2x-18=12 \n" ); document.write( "Add like terms and add 18 to both sides; \n" ); document.write( "5x=12+18 \n" ); document.write( "5x=30 \n" ); document.write( "Divide each side by 5; \n" ); document.write( " \n" ); document.write( "x=6 \n" ); document.write( "Now we know what x= so plug it into equation to find y; \n" ); document.write( "3(6)-2y=12 \n" ); document.write( "18-2y=12 \n" ); document.write( "-2y=-6 \n" ); document.write( "y=3 \n" ); document.write( "Don't forget to check your answer; \n" ); document.write( "Hope I didn't lose you, I know there is a lot of steps \n" ); document.write( "=) \n" ); document.write( " |