document.write( "Question 1183976: The third angle of an isosceles triangle is 8° more than twice as large as each base angle. Find the measure in degrees of each base angle? \n" ); document.write( "

Algebra.Com's Answer #814499 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "The third angle of an isosceles triangle is 8° more than twice as large as each base angle.
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document.write( "Let x be the measure of a base angle.\r\n" );
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document.write( "Then the measure of the other base angle is x, again,\r\n" );
document.write( "and the measure of the third angle (the \"vertex\" angle) is 2x+8 degrees.\r\n" );
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document.write( "Since the sum of interior angles of any triangle is 180 degrees, we have this equation\r\n" );
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document.write( "    x + x + (2x+8) = 180,\r\n" );
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document.write( "which implies\r\n" );
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document.write( "    4x + 8 = 180,\r\n" );
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document.write( "       4x  = 180 - 8 = 172\r\n" );
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document.write( "        x            = 172/4 = 43  degrees.\r\n" );
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document.write( "ANSWER.  The measure of each base angle is 43 degrees.\r\n" );
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