document.write( "Question 1183930: Let ax^2 + bx + c = 0 be a quadratic equation with no real roots and a,b > 0.
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Algebra.Com's Answer #814445 by ikleyn(52781)\"\" \"About 
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document.write( "Let p and q be the roots of the given equation,\r\n" );
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document.write( "The harmonic mean  of the roots is\r\n" );
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document.write( "    H = \"2%2F%281%2Fp+%2B+1%2Fq%29\" = \"%282pq%29%2F%28p%2Bq%29\".\r\n" );
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document.write( "According to Vieta's theorem,  pq = \"c%2Fa\",  p+q = \"-b%2Fa\",  so\r\n" );
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document.write( "    H = \"%282pq%29%2F%28p%2Bq%29\" = \"%282%2A%28c%2Fa%29%29%2F%28%28-b%2Fa%29%29\" = \"-%282c%29%2Fb\".\r\n" );
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document.write( "Thus the inequality we need to prove takes the form\r\n" );
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document.write( "    \"-b%2F%282a%29\" > \"-%282c%29%2Fb\".\r\n" );
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document.write( "It is equivalent to\r\n" );
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document.write( "    \"b%2F2a\" < \"%282c%29%2Fb\"\r\n" );
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document.write( "which with positive \"a\" and \"b\" is equivalent to\r\n" );
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document.write( "    b^2 < 4ac,   or   b^2 - 4ac < 0.\r\n" );
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document.write( "The last inequality is equivalent to the condition that the given quadratic equation has no real roots.\r\n" );
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