document.write( "Question 1183921: a:b=2:5 and a:c=3:7. What is c:b?
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document.write( "A. 5:7
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document.write( "B. 14:15
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document.write( "C. 2:7
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document.write( "D. 15:14
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document.write( "E. 7:5 \n" );
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Algebra.Com's Answer #814435 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "I would solve this problem by a very different method from the similar ones used by the other two tutors; I have a particular dislike for that \"product of the means equals product of the extremes\" rule, since it introduces unneeded new vocabulary. \n" ); document.write( "Given the ratio of a:b and the ratio of a:c, and needing to find the ratio c:b, I would rewrite the second ratio as c:a; then I would \"eliminate the middle man\" in the ratios c:a and a:b. \n" ); document.write( "c:a = 7:3 \n" ); document.write( "a:b = 2:5 \n" ); document.write( "rewrite each ratio as an equivalent ratio using the same number for a in both: \n" ); document.write( "c:a = 14:6 \n" ); document.write( "a:b = 6:15 \n" ); document.write( "Combine them into a ratio comparing all three numbers... \n" ); document.write( "c:a:b = 14:6:15 \n" ); document.write( "and eliminate the middle man: \n" ); document.write( "c:a = 14:15 \n" ); document.write( " \n" ); document.write( " |