document.write( "Question 1183921: a:b=2:5 and a:c=3:7. What is c:b?
\n" ); document.write( "A. 5:7
\n" ); document.write( "B. 14:15
\n" ); document.write( "C. 2:7
\n" ); document.write( "D. 15:14
\n" ); document.write( "E. 7:5
\n" ); document.write( "

Algebra.Com's Answer #814435 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "I would solve this problem by a very different method from the similar ones used by the other two tutors; I have a particular dislike for that \"product of the means equals product of the extremes\" rule, since it introduces unneeded new vocabulary.

\n" ); document.write( "Given the ratio of a:b and the ratio of a:c, and needing to find the ratio c:b, I would rewrite the second ratio as c:a; then I would \"eliminate the middle man\" in the ratios c:a and a:b.

\n" ); document.write( "c:a = 7:3
\n" ); document.write( "a:b = 2:5

\n" ); document.write( "rewrite each ratio as an equivalent ratio using the same number for a in both:

\n" ); document.write( "c:a = 14:6
\n" ); document.write( "a:b = 6:15

\n" ); document.write( "Combine them into a ratio comparing all three numbers...

\n" ); document.write( "c:a:b = 14:6:15

\n" ); document.write( "and eliminate the middle man:

\n" ); document.write( "c:a = 14:15

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