document.write( "Question 1183871: The measures of the two acute angels of a right triangle are in the ratio 1:4. The measure of the larger acute angle, in degrees, is. \n" ); document.write( "
Algebra.Com's Answer #814362 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "let the two acute angels be \"alpha\" and \"beta\"\r
\n" ); document.write( "\n" ); document.write( "if they are in the ratio \"1%3A4\", we have\r
\n" ); document.write( "\n" ); document.write( "\"alpha%3Abeta=1%3A4\"........solve for \"beta\"\r
\n" ); document.write( "\n" ); document.write( "\"beta=4alpha\".........eq.1\r
\n" ); document.write( "\n" ); document.write( "if \"alpha\" and \"beta\" are two acute angels of a right triangle, their sum is \"90\"° \r
\n" ); document.write( "\n" ); document.write( "\"alpha+%2B+beta=90\".........eq.2\r
\n" ); document.write( "\n" ); document.write( "substitute \"beta\" from eq.1\r
\n" ); document.write( "\n" ); document.write( "\"alpha%2B4alpha=90\"\r
\n" ); document.write( "\n" ); document.write( "\"5alpha=90\"\r
\n" ); document.write( "\n" ); document.write( "\"alpha=90%2F5\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28alpha=18%29\"°\r
\n" ); document.write( "\n" ); document.write( "then\r
\n" ); document.write( "\n" ); document.write( "\"beta=4%2A18\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28beta=72%29\"°\r
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