document.write( "Question 1183867: The polynomial of degree 5, P(x) has a leading coefficient 1, has roots of multiplicity 2 at x=5 and x=0, and a root of multiplicity 1 at x=-5. find a possible formula for P(x) \n" ); document.write( "
Algebra.Com's Answer #814356 by Solver92311(821)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "If is a zero of a polynomial function, then is a factor of the polynomial. The number of factors of the polynomial is equal to the degree of the polynomial. So your polynomial has the following factors:\r
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\n" ); document.write( "\n" ); document.write( ", which is to say \r
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\n" ); document.write( "\n" ); document.write( "The set of all 5th-degree polynomials with real coefficients that have this set of zeros can be described as:\r
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\n" ); document.write( "\n" ); document.write( "Where is the lead coefficient. Your lead coefficient is given to be 1, so:\r
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\n" ); document.write( "\n" ); document.write( "is a valid possible formula for . You could expand that, but that is a lot of extra work that is not required by the question posed.\r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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