document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1183863>Question 1183863</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One angle of a triangle is twice as large as another. The measure of the third angle is 84 degrees more than that of the smallest angle. Find the measure of each angle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #814353 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=814353\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One angle of a triangle ABC is twice as large as another.<BR>\n" );
document.write( "A = 2B<BR>\n" );
document.write( " The measure of the third angle is 84 degrees more than that of the smallest angle.<BR>\n" );
document.write( "C = B + 84<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Find the measure of each angle.<BR>\n" );
document.write( "A + B + C = 180<BR>\n" );
document.write( "Replace A with 2B and replace C with (B+84)<BR>\n" );
document.write( "2B + B + (B+84) = 180<BR>\n" );
document.write( "4B = 180 - 84<BR>\n" );
document.write( "4B = 96<BR>\n" );
document.write( "B = 96/4<BR>\n" );
document.write( "B = 24<BR>\n" );
document.write( "Then<BR>\n" );
document.write( "A = 2(24) = 48 deg<BR>\n" );
document.write( "C = 24 + 84 = 108 deg<BR>\n" );
document.write( ":<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Check: 48 + 24 + 108 = 180\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );