document.write( "Question 1183841: At a party, 1/3 of the guests drank only soda, and 2/5 of the guests drank only juice. If the remaining 16 guests had nothing to drink, then how many guests were at the party?
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Algebra.Com's Answer #814316 by Edwin McCravy(20056) $\"\"$ $\"About$

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document.write( "1/3 + 2/5 = 5/15 + 6/15 = 11/15ths of the guests drank soda or orange juice.\r\n" );
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document.write( "That left 1 - 11/15 = 15/15 - 11/15 = 4/15 who had nothing to drink.\r\n" );
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document.write( "Let x represent the number of guests: \r\n" );
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document.write( "Multiply both sides by the reciprocal 15/4:\r\n" );
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document.write( "There were 60 guests.\r\n" );
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document.write( "Edwin

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