document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1183824>Question 1183824</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the general rule of the following sequence. Show your solution<BR>\n" );
document.write( "1/2,2,27/8,4,...<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #814298 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=814298\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "1/2, 2, 27/8, 4, ...<br><BR>\n" );
document.write( "Given that the 1st and 3rd terms are fractions but the others are not, rewrite the sequence as all fractions, using denominators that form a recognizable pattern.<br><BR>\n" );
document.write( "The denominator of the 1st term is 2; the denominator of the 3rd term is 8.  So one \"nice\" pattern for the denominators would be 2, 4, 8, 16, ....  Using those denominators, the sequence is<br><BR>\n" );
document.write( "1/2, 8/4, 27/8, 64/16, ...<br><BR>\n" );
document.write( "The numerators are now 1, 8, 27, 64, ..., which are 1^3, 2^3, 3^3, and 4^3.  So the pattern for the sequence appears to be<br><BR>\n" );
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