document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1183758>Question 1183758</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A batch of pills consist of 10 good pills and 4 that are defective (contain the wrong amount of the drug). If 5 pills are randomly selected without replacement, what is the probability that all 4 of the defective pills are selected? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #814230 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=814230\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 14 pills and 14C5 ways to choose or 2002 ways.<BR>\n" );
document.write( "5 ways to choose 4 pills and the last pill is always good, so 5/2002=0.00250 probability.<BR>\n" );
document.write( "5C4*1/14C5\r<BR>\n" );
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document.write( "also, (10/14) ways for the first (4/13)(3/12)(2/11)(1/10) for the rest, and 5 ways that can happen with same numerator/denominator, each =240/240240,  and that is the same probability. </SPAN>\n" );
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