document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1183768>Question 1183768</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the intensity at which an object is illuminated varies inversely as the square of its distance from the light source at 1.5 feet from a light bulb the intensity of the light is 60 units what is the intensity at 1 feet </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #814214 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=814214\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I=k/d^2 is the basic formula<BR>\n" );
document.write( "60=k/1.5^2<BR>\n" );
document.write( "k=135<BR>\n" );
document.write( "so <BR>\n" );
document.write( "I=135/1^2<BR>\n" );
document.write( "=135 units at one foot. </SPAN>\n" );
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