document.write( "Question 1183763: A three-digit number whose hundreds digit is twice the tens digit and the tens digit is 3 more that
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Algebra.Com's Answer #814211 by MathTherapy(10552) $\"\"$ $\"About$

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\n" ); document.write( " A three-digit number whose hundreds digit is twice the tens digit and the tens digit is 3 more that
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Let units digits be U\r\n" );
document.write( "Then tens digit = U + 3, and hundreds digit is: 2T, or 2(U + 3) = 2U + 6\r\n" );
document.write( "By observation, with the hundreds digit being 2U + 6, U or the units digit CANNOT be 2 or more. \r\n" );
document.write( "Therefore, U or the units digit MUST either be 0 or 1.\r\n" );
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document.write( "First case: Units digit = 0 \r\n" );
document.write( "Tens digit = 0 + 3 = 3\r\n" );
document.write( "Hundreds digit = 2(0) + 6 = 6\r\n" );
document.write( "Number, based on the above: \r\n" );
document.write( " 				\r\n" );
document.write( "Second case: Units digit = 1 \r\n" );
document.write( "Tens digit = 1 + 3 = 4\r\n" );
document.write( "Hundreds digit = 2(1) + 6 = 8\r\n" );
document.write( "Number, based on the above:

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