document.write( "Question 1183743: I am confused on how to solve this, may you please help?\r
\n" ); document.write( "\n" ); document.write( "Use a factorial, permutation or combination to find the probability of the given event. Do NOT simplify your answer. Only consider digits greater than zero.\r
\n" ); document.write( "\n" ); document.write( "Bill forgot the last three digits of his 8 digit password. He only remembers that the digits are even and not the same. What is the probability he enters the correct password on the first try?
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Algebra.Com's Answer #814199 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The other tutor goes through a lengthy explanation of why there are only 24 possible sequences (permutations) of the last three digits, so that the probability of getting the right password on the first attempt is 1/24.

\n" ); document.write( "That is quite possibly the answer the author of the problem wanted; however, grammatically it is not the right answer.

\n" ); document.write( "The problem is with the phrasing of the question, which says the three last digits are \"even and not the same\".

\n" ); document.write( "That does NOT mean the same thing as \"even and all different\". For example, the digits 224 are all even and not the same....

\n" ); document.write( "So with the way the problem is stated, the only sequences NOT allowed are 222, 444, 666, and 888.

\n" ); document.write( "Without restrictions, the number of possible permutations of the last three digits is 4*4*4=64; with the 4 excluded ones, the number of allowable permutations is 64-4=60. And of course only one of them is the correct one.

\n" ); document.write( "ANSWER: The probability of entering the correct password on the first try is 1/60.

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