document.write( "Question 1183710: 11) Create a graph of a function given the following information:
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document.write( "• The instantaneous rate of change at x = 2
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document.write( "is zero.
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document.write( "• The instantaneous rate of change at x = 3
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document.write( "is negative.
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document.write( "• The average rate of change on the interval 0 <= x <= 4 is zero. \n" );
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Algebra.Com's Answer #814150 by greenestamps(13203)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Average rate of change on [0,4] zero means f(0)=f(4). \n" ); document.write( "Instantaneous rate of change zero at x=2 means there is a local maximum or minimum at x=2. \n" ); document.write( "Those two conditions together are easily satisfied by a function of the form \n" ); document.write( " \n" ); document.write( "To have the instantaneous rate of change negative at x=3, we simply need to make the parabola open downward, which means a is negative. \n" ); document.write( "So one simple function satisfying the given conditions is \n" ); document.write( " \n" ); document.write( "A graph.... \n" ); document.write( " \n" ); document.write( "(1) f(0)=f(4)=-4 \n" ); document.write( "(2) f'(2)=0 \n" ); document.write( "(3) f'(3)<0 \n" ); document.write( "A sinusoidal function can also be found that satisfies the given conditions: \n" ); document.write( "f(0)=f(4) means the period of the function can be 4 \n" ); document.write( "f'(2)=0 and f'(3)<0 means we want a local maximum at x=2 \n" ); document.write( "This function satisfies those conditions: \n" ); document.write( " \n" ); document.write( "A graph.... \n" ); document.write( " \n" ); document.write( "(1) f(0)=f(4)=-1 \n" ); document.write( "(2) f'(2)=0 \n" ); document.write( "(3) f'(3)<0 \n" ); document.write( " \n" ); document.write( " |