document.write( "Question 1183710: 11) Create a graph of a function given the following information:
\n" ); document.write( "• The instantaneous rate of change at x = 2
\n" ); document.write( "is zero.
\n" ); document.write( "• The instantaneous rate of change at x = 3
\n" ); document.write( "is negative.
\n" ); document.write( "• The average rate of change on the interval 0 <= x <= 4 is zero.
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Algebra.Com's Answer #814149 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "The instantaneous rate of change at \"x+=+2\" is zero.
\n" ); document.write( "Means: A peak trough or inflection. The curve levels off there; the tangent is parallel to the x-axis.\r
\n" ); document.write( "\n" ); document.write( "The instantaneous rate of change at \"x+=+3\" is negative.
\n" ); document.write( "Means: There's a downward slop at \"x=3\"\r
\n" ); document.write( "\n" ); document.write( "The average rate of change on the interval\"+0+%3C=x+%3C=4\" is zero.
\n" ); document.write( "Means: It's symmetric over the interval - for every up there is a down, and you end as high as you start.\r
\n" ); document.write( "\n" ); document.write( "Thus: It's a hill. Plot a parabola with a peak at \"x=2\".\r
\n" ); document.write( "\n" ); document.write( "or, plot a curve between points:\r
\n" ); document.write( "\n" ); document.write( "(\"0\",\"0\") ,(\"1\",\"3\") ,(\"2\",\"4\") ,(\"3\",\"3\") (\"4\",\"0\")\r
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\n" ); document.write( "\n" ); document.write( "\"download\"\r
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\n" ); document.write( "\n" ); document.write( "you can also find equation using the points above\r
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\n" ); document.write( "\n" ); document.write( "\"y=ax%5E2%2Bbx%2Bc\"..........(\"0\",\"0\")\r
\n" ); document.write( "\n" ); document.write( "\"0=a%2A0%5E2%2Bb%2A0%2Bc\"
\n" ); document.write( "\"c=0\"\r
\n" ); document.write( "\n" ); document.write( "\"3=a%2A1%5E2%2Bb%2A1\" ..........(\"1\",\"3\")
\n" ); document.write( "\"3=a%2Bb\"............eq.1 \r
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\n" ); document.write( "\n" ); document.write( "\"4=a%2A2%5E2%2Bb%2A2+\"..............(\"2\",\"4\")
\n" ); document.write( "\"4=4a%2B2b\"......divide by \"2\"\r
\n" ); document.write( "\n" ); document.write( "\"2=2a%2Bb\"......eq.2 \r
\n" ); document.write( "\n" ); document.write( "from eq.1 and eq.2 we have system\r
\n" ); document.write( "\n" ); document.write( "\"a%2Bb-3=0\"
\n" ); document.write( "\"2a%2Bb-2=0\"
\n" ); document.write( "------------------------------
\n" ); document.write( "\"2a%2B2b-6=0\"...........multiply by \"2\"
\n" ); document.write( "\"2a%2Bb-2=0\"
\n" ); document.write( "------------------------subtract
\n" ); document.write( "\"2a%2B2b-6-2a-b%2B2=0\"
\n" ); document.write( "\"b-4=0\"
\n" ); document.write( "\"b=4\"\r
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\n" ); document.write( "\n" ); document.write( "\"3=a%2Bb\"............eq.1
\n" ); document.write( "\"3=a%2B4\"
\n" ); document.write( "\"a=3-4\"
\n" ); document.write( "\"a+=+-1+\"\r
\n" ); document.write( "\n" ); document.write( "\"y=-x%5E2%2B4x\"\r
\n" ); document.write( "\n" ); document.write( "vertex | (\"2\", \"4\")\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "check the average rate of change of \"f%28x%29=-x%5E2%2B4x\" on the interval [\"0\",\"4\"]\r
\n" ); document.write( "\n" ); document.write( "the average rate of change of \"f%28x%29\" on the interval [\"a\",\"b\"] is
\n" ); document.write( "\"%28f%28b%29-f%28a%29%29%2F%28b-a%29\"\r
\n" ); document.write( "\n" ); document.write( "we have that \"a=0\", \"b=4\"\r
\n" ); document.write( "\n" ); document.write( "\"f%280%29=-0%5E2%2B4%2A0=0\"
\n" ); document.write( "\"f%284%29=-4%5E2%2B4%2A4=0\"\r
\n" ); document.write( "\n" ); document.write( "thus, \"%28f%28b%29-f%28a%29%29%2F%28b-a%29=%280-0%29%2F%284-0%29=0\"\r
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