document.write( "Question 1183702: Suppose you work for a small company with delivery vans. The business has three drivers who deliver packages to private individuals.\r
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document.write( "Driver 1 takes 30% of the runs but delivers to the wrong address in 5% of the runs\r
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document.write( "Driver 2 takes 20% of the journeys but delivers to the wrong address in 2% of the journeys\r
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document.write( "Driver 3 takes 50% of the runs but delivers to the wrong address in 10% of the runs\r
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document.write( "1. What proportion of deliveries go to the right address?\r
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document.write( "2. What is the probability that the latest package that arrived at the correct address was delivered by Driver 3?\r
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document.write( "3. Assume that you have now received a complaint from a customer who has not received their package. What is the probability that that delivery would have been delivered by Driver 1? \n" );
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Algebra.Com's Answer #814134 by robertb(5830) You can put this solution on YOUR website! 1. P(correct address) = P(correct address AND driver 1) + P(correct address AND driver 2) + P(correct address AND driver 3) = 0.285 + 0.196 + 0.45 = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "*** \n" ); document.write( "(Rather funny)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2. P(driver 3| correct address) = P(correct address AND driver 3)/P(correct address) = 0.45/0.931 = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3. P(driver 1| wrong address) = P(wrong address AND driver 1)/P(wrong address) = 0.015/0.069 = \n" ); document.write( " \n" ); document.write( " |