document.write( "Question 1183676: Find the equation, in standard form, of the circle.
\n" ); document.write( "Diameter with endpoints (-2,-1) and (6,-3) \n" ); document.write( "
Algebra.Com's Answer #814121 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Find the equation, in standard form, of the circle.
\n" ); document.write( "Diameter with endpoints (-2,-1) and (6,-3)
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If you want to confuse someone or yourself to death, then use the many variables that the other person presented to you. 
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document.write( "If not, then just use the MIDPOINT formula: , to get:
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document.write( "                                            \"matrix%281%2C5%2C+%22%282%2C%22%2C+%22-+2%29%2C%22%2C+or%2C+%22%28h%2C%22%2C+%22k%29%22%29\" <===== CENTER coordinates of circle
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document.write( "Standard form of the equation of a CIRCLE: \"matrix%281%2C3%2C+%28x+-+h%29%5E2+%2B+%28y+-+k%29%5E2%2C+%22=%22%2C+r%5E2%29\"
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document.write( "                                           \"matrix%281%2C3%2C+%28-+2+-+2%29%5E2+%2B+%28-+1+-+-+2%29%5E2%2C+%22=%22%2C+r%5E2%29\" ------ In the ABOVE, substituting (2, - 2) for (h, k) and (- 2, - 1) for (x, y). NOTE that (6, - 3) could also be used for (x, y)
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document.write( "For the equation in Standard form, we finally get:  \n" );
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