document.write( "Question 1183676: Find the equation, in standard form, of the circle.
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Algebra.Com's Answer #814100 by ikleyn(52782)\"\" \"About 
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document.write( "The center's  x-coordinate is  \"%28-2+%2B+6%29%2F2\" = \"4%2F2\" = 2.\r\n" );
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document.write( "The center's  y-coordinate is  \"%28-1+%2B+%28-3%29%29%2F2\" = \"-4%2F2\" = -2.\r\n" );
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document.write( "The square of the diameter's length is  d^2 = ((6-(-2))^2 + ((-3)-(-1))^2 = (8^2 + 2^2) = 68.\r\n" );
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document.write( "The square of the radius is  r^2 = 68/2^2 = 68/4 = 17.\r\n" );
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document.write( "The standard form equation of the circle is\r\n" );
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document.write( "    \"%28x-2%29%5E2\" + \"%28y%2B2%29%5E2\" = 17.\r\n" );
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\n" ); document.write( "\n" ); document.write( "The post by @josgarithmetic is  TOTALLY  WRONG.\r
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\n" ); document.write( "\n" ); document.write( "IGNORE  it,  for the sake of your safety.\r
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