document.write( "Question 1183652:
\n" ); document.write( " Suppose the annual savings (in millions of euros) of a specific household is a random variable, which follows the normal distribution with mean μ=5 and standard deviation σ=1. If we take a random sample of 16 households from the population, what is the probability the sampling mean to be:\r
\n" ); document.write( "\n" ); document.write( " more than 5.5 million euros?
\n" ); document.write( " between 4.9 and 5.1 million euros?
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Algebra.Com's Answer #814070 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
when you're dealing with the mean of a sample, then you have to use the standard error.\r
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\n" ); document.write( "\n" ); document.write( "standard error = standard deviation / square root of sample size.\r
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\n" ); document.write( "\n" ); document.write( "use of an online calculator helps.
\n" ); document.write( "here's one for z-scores.
\n" ); document.write( "https://davidmlane.com/hyperstat/z_table.html\r
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\n" ); document.write( "\n" ); document.write( "if you are using the population standard deviation, then use the z-score if the sample size is greater than 30, otherwise use the t-score.\r
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\n" ); document.write( "\n" ); document.write( "here's a reference.\r
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\n" ); document.write( "\n" ); document.write( "https://math.stackexchange.com/questions/1817980/how-to-know-when-to-use-t-value-or-z-value\r
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\n" ); document.write( "\n" ); document.write( "your problem is using the standard deviation from the population, but the sample size is less than 30, so use of the t-score is indicated.\r
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\n" ); document.write( "\n" ); document.write( "i'll do both so you can see the difference, but your official answer should be from the t-score unless the problem doesn't care whether you use the t-score or the z-score.
\n" ); document.write( "that you need to get from your professor.\r
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\n" ); document.write( "\n" ); document.write( "using the z-score ********************************************\r
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\n" ); document.write( "\n" ); document.write( "z = (x - m) / s\r
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\n" ); document.write( "\n" ); document.write( "z is the z-score
\n" ); document.write( "x is the raw score
\n" ); document.write( "m is the raw mean
\n" ); document.write( "s is the standard error.\r
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\n" ); document.write( "\n" ); document.write( "s = standard deviation from the population divided by square root of sample size = 1 / sqrt(16) = 1/4 = .25.\r
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\n" ); document.write( "\n" ); document.write( "z-score for 5.5 million euros becomes:
\n" ); document.write( "z = (5.5 - 5) / .25 = 2\r
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\n" ); document.write( "\n" ); document.write( "you will be looking for the area under the normal distribution curve to the right of a z-score of 2.
\n" ); document.write( "that area will be .0228 rounded to 4 decimal places. *****\r
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\n" ); document.write( "\n" ); document.write( "the area to the right of the z-score is the probability that you will get a z-score greater than 2.\r
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\n" ); document.write( "\n" ); document.write( "here is a graph of the results using the z-score.\r
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\n" ); document.write( "\n" ); document.write( "z-score for 4.9 million euros becomes:
\n" ); document.write( "z = 4.9 - 5) / .25 = -.4
\n" ); document.write( "z-score for 5.1 million euros becomes:
\n" ); document.write( "z = (5.1 - 5) / .25 = .4\r
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\n" ); document.write( "\n" ); document.write( "you will be looking for the area under the normal distribution curve between z = -.4 and z = .4
\n" ); document.write( "that area will be .31084 rounded to 5 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "same standard error is used.\r
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\n" ); document.write( "\n" ); document.write( "here is a graph of the results using the z-score.\r
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\n" ); document.write( "\n" ); document.write( "using the t-score **************************************\r
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\n" ); document.write( "\n" ); document.write( "when you are using the t-score, you need to use the degrees of freedom.
\n" ); document.write( "for simple problem, such as this, the degrees of freedom are equal to the sample size minus of 1.\r
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\n" ); document.write( "\n" ); document.write( "your degrees of freedom are 15.\r
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\n" ); document.write( "\n" ); document.write( "your calculation of the t-score is the same, i.e......
\n" ); document.write( "t = (x - m) / s\r
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\n" ); document.write( "\n" ); document.write( "x is the same.
\n" ); document.write( "m is the same.
\n" ); document.write( "s is the same.\r
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\n" ); document.write( "\n" ); document.write( "what will be different is the area to under the normal distribution curve.\r
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\n" ); document.write( "\n" ); document.write( "for area to the right of 5.5, the t-score will be 2.
\n" ); document.write( "the area to the right of that t-score with 15 degrees of freedom will be equal to .031972502 = .032 rounded to 3 decimal places, as in the graphical display below.\r
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\n" ); document.write( "\n" ); document.write( "for area between t-score of -.4 and.4, the area in between will be equal to .3052050642 = .3052 rounded to 4 decimal places, as in the graphical display below.\r
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\n" ); document.write( "\n" ); document.write( "the difference in the area between the z-score and the t-score are greater when the sample size is smaller and gets less as the sample size grows larger.\r
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\n" ); document.write( "\n" ); document.write( "the z-score calculator can be found at https://davidmlane.com/hyperstat/z_table.html\r
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\n" ); document.write( "\n" ); document.write( "the t-score calculator can be found at https://mathcracker.com/t-distribution-graph-generator#results\r
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\n" ); document.write( "\n" ); document.write( "for my own calculations, i used the TI-84 plus calculator.
\n" ); document.write( "it provides results to a greater degree of accurac6y (more decimal places).\r
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