document.write( "Question 1183651:
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document.write( " Life insurance salesman meets his prospective customers separately. At each meeting, he makes the same effort to persuade the prospective client to be insured. The vendor's understanding after a long term in the insurance business is that the probability of persuading the customer to be insured (probability of success) is 0,1. What is the probability in 4 trials to insure one of them? \n" );
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Algebra.Com's Answer #814063 by ikleyn(52949) You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "It is the binomial distribution probability problem.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The formula and the answer are\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " P =\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To see many other similar (and different) solved problems on the binomial distribution, look into the lessons\r \n" ); document.write( "\n" ); document.write( " - Simple and simplest probability problems on Binomial distribution \r \n" ); document.write( "\n" ); document.write( " - Typical binomial distribution probability problems \r \n" ); document.write( "\n" ); document.write( "in this site.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |