document.write( "Question 1183651:
\n" ); document.write( " Life insurance salesman meets his prospective customers separately. At each meeting, he makes the same effort to persuade the prospective client to be insured. The vendor's understanding after a long term in the insurance business is that the probability of persuading the customer to be insured (probability of success) is 0,1. What is the probability in 4 trials to insure one of them?
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Algebra.Com's Answer #814063 by ikleyn(52949)\"\" \"About 
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document.write( "It is the binomial distribution probability problem.\r\n" );
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document.write( "The formula and the answer are\r\n" );
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document.write( "    P = \"C%5B4%5D%5E1%2A0.1%5E1%2A%281-0.1%29%5E3\" = \"4%2A0.1%2A0.9%5E3\" = 0.2916.\r\n" );
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\n" ); document.write( "\n" ); document.write( "To see many other similar  (and different)  solved problems on the binomial distribution,  look into the lessons\r
\n" ); document.write( "\n" ); document.write( "    - Simple and simplest probability problems on Binomial distribution \r
\n" ); document.write( "\n" ); document.write( "    - Typical binomial distribution probability problems \r
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