document.write( "Question 1183640: A man leaves his house at 8:00 AM and traveling at an average speed of 2 kph, arrives at his office 3 min ahead of the expected time. Had he left his house at 8:30 am and traveled at an average speed of 3 kph, he will arrive 6 min late of the expected time. Find the distance that he had traveled. \n" ); document.write( "
Algebra.Com's Answer #814042 by ikleyn(52797)\"\" \"About 
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\n" ); document.write( "A man leaves his house at 8:00 AM and traveling at an average speed of 2 kph, arrives at his office
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\n" ); document.write( "\n" ); document.write( "            As the problem is worded,  it may perplex the reader.\r
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document.write( "    A man leaves his house at 8:00 AM and traveling at an average speed of 2 kph, arrives at his office \r\n" );
document.write( "    3 min ahead of the \"highlight%28cross%28expected%29%29\" scheduled time. \r\n" );
document.write( "    Had he left his house at 8:30 am and traveled at an average speed of 3 kph, \r\n" );
document.write( "    he will arrive 6 min late of the \"highlight%28cross%28expected%29%29\" scheduled time. \r\n" );
document.write( "    Find the distance that he had traveled.\r\n" );
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document.write( "Let d be the distance from the house to the office.\r\n" );
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document.write( "The travel time in the first  scenario is  \"d%2F2\"  hours.\r\n" );
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document.write( "The travel time in the second scenario is  \"d%2F3\"  hours.\r\n" );
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document.write( "The difference of the travel times is  (t - 8:00 - 3) - ((t+6) - 8:30) = 30 -3 - 6 = 21 minutes, or \"21%2F60\" of an hour,\r\n" );
document.write( "where \"t\" is the scheduled time clock reading.\r\n" );
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document.write( "It gives the time equation\r\n" );
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document.write( "     \"d%2F2\" - \"d%2F3\" = \"21%2F60\"    hours\r\n" );
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document.write( "to find \"t\".   To solve the equation, multiply both sides by 60.  You will get\r\n" );
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document.write( "    30d - 20d = 21\r\n" );
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document.write( "       10d    = 21\r\n" );
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document.write( "        d     = 21/10 = 2.1 miles.    ANSWER\r\n" );
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document.write( "ANSWER.  The distance from home to the office is  2.1 miles.\r\n" );
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document.write( "CHECK.  The travel time in the first scenario is  \"2.1%2F2\" = 1.05 hours = 1 hour and 3 minute.\r\n" );
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document.write( "        Hence, the appointment time (scheduled arriving time) is 9:06 am.\r\n" );
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document.write( "        In the second scenario, his travel time was  \"2.1%2F3\" = 0.7 of an hour, or 42 minutes; \r\n" );
document.write( "                                he started at 8:30 am, hence, he arrived at 9:12 am, which is  6 minutes later \r\n" );
document.write( "                                than the scheduled arriving time of 9:06 am.\r\n" );
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document.write( "        ! Correct !\r\n" );
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