document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1183631>Question 1183631</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a single lane 12ft wide goes through a semicircular tunnel with radius 9ft. how high is the tunnel at the edge of each lane? (round off to 2 decimal places) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #814041 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=814041\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The equation of the circle using the tunnel height as the y-axis and the width of the lane as the x-axis, and the origin in the middle is x^2+y^2=81<BR>\n" );
document.write( "At the edge of the lane is at (6, 0) or (-6, 0)<BR>\n" );
document.write( "so 36+y^2=81<BR>\n" );
document.write( "y=sqrt(45) feet tall or 3 sqrt(5)=6.71 feet tall.<BR>\n" );
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