document.write( "Question 1183607: Locate the center, vertices, the foci, and the ends of the latera recta then graph the ellipse whose equation is 4x²+9y²-16x+18y-11=0. \n" ); document.write( "
Algebra.Com's Answer #814022 by KMST(5328)\"\" \"About 
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\"4x%5E2%2B9y%5E2-16x%2B18y-11=0\"
\n" ); document.write( "\"4%28x%5E2-4x%29%2B9%28y%5E2%2B2y%29=11\"
\n" ); document.write( "\"4%28x%5E2-4x%2B4%29%2B9%28y%5E2%2B2y%2B1%29=11%2B4%2A4%2B9%2A1\"
\n" ); document.write( "\"4%28x-2%29%5E2%2B9%28y%2B1%29%5E2=11%2B16%2B9\"
\n" ); document.write( "\"4%28x-2%29%5E2%2B9%28y%2B1%29%5E2=36\"
\n" ); document.write( "The equation above shows that that \"system%28x-2=0%2Cy%2B1=0%29\" or \"system%28x=2%2Cy=-1%29\" are axes (of symmetry) of the ellipse.
\n" ); document.write( "The center of the ellipse is the point where they intersect:
\n" ); document.write( "the point \"P%282%2C-1%29\"
\n" ); document.write( "Your teacher may like to write the equation as \"%28x-2%29%5E2%2F9%2B%28y%2B1%29%5E2%2F4=1\" or \"%28x-2%29%5E2%2F3%5E2%2B%28y%2B1%29%5E2%2F2%5E2=1\" ,
\n" ); document.write( "dividing by \"36\" both sides of
\n" ); document.write( "\"4%28x-2%29%5E2%2B9%28y%2B1%29%5E2=36\" .
\n" ); document.write( "They are just equivalent equations for the same ellipse.
\n" ); document.write( "You could say they show more clearly that for all the points of the ellipse
\n" ); document.write( "\"%28x-2%29%5E2%2F9%3C=1\" --> \"abs%28x-2%29%3C=3\" and \"%28y%2B1%29%5E2%2F4%3C=1\" --> \"abs%28y%2B1%29%3C=2\"
\n" ); document.write( "They also show that the vertices of the ellipse are on the axes at \"system%28y=-1%2Cx=2+%2B-+3%29\" and \"system%28x=2%2Cy=-1+%2B-+2%29\"
\n" ); document.write( "at \"A%28-1%2C-1%29\" , \"B%285%2C-1%29\" , \"C%282%2C1%29\" , and \"D%282%2C-3%29\" .
\n" ); document.write( "The segment AB, on the \"horizontal\" \"y=-1\" axis, is called the major axis, because for this ellipse it is longer, going \"a=3\" units to left and right of the center of the ellipse.
\n" ); document.write( "The segment CD, on the \"vertical\" \"x=2\" axis, is called the minor axis, because for this ellipse it is shorter, going \"b=2\" units up and down from the center of the ellipse.
\n" ); document.write( "The foci are on the major axis at a distance \"c\" to both sides of the center, and we calculate \"c\" from \"a%5E2=b%5E2%2Bc%5E2\" .
\n" ); document.write( "\"c=sqrt%283%5E2-2%5E2%29=sqrt%289-4%29=sqrt%285%29\" .
\n" ); document.write( "Soo the coordinates of the foci are \"system%28y=-1%2C+x=2+%2B-sqrt%285%29%29\" .
\n" ); document.write( "The ends of the latera recta are the points on the ellipse with the same \"x\"\"%22=%22\"\"2+%2B-sqrt%285%29\"\"%22=%22\"\"approximately\"\"2%2B-+2.236\" as the foci.
\n" ); document.write( "For those points \"x-2=%22+%22+%2B-sqrt%285%29\" , so \"%28x-2%29%5E2=5\"
\n" ); document.write( "The \"y\" coordinates for those points can be calculated from \"4%28x-2%29%5E2%2B9%28y%2B1%29%5E2=36\" as
\n" ); document.write( "\"4%2A5%2B9%28y%2B1%29%5E2=36\"-->\"20%2B9%28y%2B1%29%5E2=36\"-->\"9%28y%2B1%29%5E2=16\"-->\"%28y%2B1%29%5E2=16%2F9\"-->\"y%2B1=%22+%22+%2B-sqrt%2816%2F9%29\"-->\"y=-1+%2B-+4%2F3\"
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