document.write( "Question 16682: b + 2 = 27 + 2b/ 3
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Algebra.Com's Answer #8140 by elima(1433)\"\" \"About 
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b + 2 = 27 + 2b/ 3
\n" ); document.write( "First subtract 27 from each side;
\n" ); document.write( "b+2-27=27+\"2b%2F3\"-27
\n" ); document.write( "b-25=\"2b%2F3\"
\n" ); document.write( "Now multiply each side by 3;
\n" ); document.write( "(3)b-25=\"2b%2F3\"(3)
\n" ); document.write( "3b-75=2b
\n" ); document.write( "Add 75 to each side;
\n" ); document.write( "3b-75+75=2b+75
\n" ); document.write( "3b=2b+75
\n" ); document.write( "Subtract 2b from each sidel
\n" ); document.write( "3b-2b=2b+75-2b
\n" ); document.write( "b=75
\n" ); document.write( "Don't forget to check your answer
\n" ); document.write( "Hope you understand
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