document.write( "Question 16682: b + 2 = 27 + 2b/ 3
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Algebra.Com's Answer #8140 by elima(1433)![]() ![]() ![]() You can put this solution on YOUR website! b + 2 = 27 + 2b/ 3 \n" ); document.write( "First subtract 27 from each side; \n" ); document.write( "b+2-27=27+ \n" ); document.write( "b-25= \n" ); document.write( "Now multiply each side by 3; \n" ); document.write( "(3)b-25= \n" ); document.write( "3b-75=2b \n" ); document.write( "Add 75 to each side; \n" ); document.write( "3b-75+75=2b+75 \n" ); document.write( "3b=2b+75 \n" ); document.write( "Subtract 2b from each sidel \n" ); document.write( "3b-2b=2b+75-2b \n" ); document.write( "b=75 \n" ); document.write( "Don't forget to check your answer \n" ); document.write( "Hope you understand \n" ); document.write( "=) \n" ); document.write( " |