document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1183587>Question 1183587</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given <BR>\n" );
document.write( "f(x) = sqrt x and g(x) = x^2 − 25, evaluate each expression.\r<BR>\n" );
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document.write( "f(g(5))=\r<BR>\n" );
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document.write( "g(f(5))=\r<BR>\n" );
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document.write( "g(f(0))=\r<BR>\n" );
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document.write( "f(g(−6))=\r<BR>\n" );
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document.write( "f(g(x))=\r<BR>\n" );
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document.write( "g(f(x))=<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #813976 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=813976\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> g(5)=0, and sqrt (0)=0<BR>\n" );
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document.write( "f(5)=sqrt(5) and sqrt(5)^2-25=-20<BR>\n" );
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document.write( "f(0)=0 and g(0)=-25<BR>\n" );
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document.write( "g(-6)=11 and f(11)=sqrt(11)<BR>\n" );
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document.write( "f(g(x))=sqrt(x^2-25)<BR>\n" );
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document.write( "g(f(x))=x-25, put the sqrt(x) into the x part of g(x), so that squaring it becomes x and the -25 is still there. </SPAN>\n" );
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