document.write( "Question 1183584: f(x)= -x-2
\n" ); document.write( "find f(-3)
\n" ); document.write( " f(-3)=Why is -(-3)-2
\n" ); document.write( "=f(-3)= 3-2
\n" ); document.write( "f(-3)= 1 \n" ); document.write( "

Algebra.Com's Answer #813965 by MathLover1(20850) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"f%28-3%29\"$ =Why is $\"+-%28-3%29-2\"$ \r
\n" ); document.write( "\n" ); document.write( "you are given\r
\n" ); document.write( "\n" ); document.write( " $\"f%28x%29=+-x-2\"$ -> note you have minus sign in front of $\"x\"$ , or your equation is $\"f%28x%29=+-1%2Ahighlight%28x%29-2\"$ \r
\n" ); document.write( "\n" ); document.write( "if you need to find $\"f%28-3%29\"$ , it means the value of $\"x\"$ is $\"-3\"$ , or simply $\"x=-3\"$ \r
\n" ); document.write( "\n" ); document.write( "then you go to $\"f%28x%29=+-1%2Ahighlight%28x%29-2\"$ , substitute $\"x\"$ with $\"-3\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"f%28x%29=+-1%2Ahighlight%28-3%29-2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"f%28x%29=+3-2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"f%28x%29=1\"$ \r
\n" ); document.write( "
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