document.write( "Question 111488: How do you solve?\r
\n" ); document.write( "\n" ); document.write( "11 - 5log3 (x - 5) = 6\r
\n" ); document.write( "\n" ); document.write( "log x = 1 - log(x + 3)\r
\n" ); document.write( "\n" ); document.write( "and \r
\n" ); document.write( "\n" ); document.write( "e^6^y = 25\r
\n" ); document.write( "\n" ); document.write( "Thanks in advanced.
\n" ); document.write( "

Algebra.Com's Answer #81395 by wgunther(43)\"\" \"About 
You can put this solution on YOUR website!
first one, \"11+-+5log3+%28x+-+5%29+=+6\"
\n" ); document.write( "\"+5log_3+%28x+-+5%29+=+5+\"
\n" ); document.write( "\"+log_3+%28x-5%29+=+1+\"
\n" ); document.write( "At this point you can take both sides to be exponents of 3
\n" ); document.write( "\"+3%5E%28log_3+%28x+-+5%29%29+=+3%5E6\"
\n" ); document.write( "\"x-5=3%5E6\"
\n" ); document.write( "\"x=3%5E6%2B5\"
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\n" ); document.write( "second one \"log+x+=+1+-+log%28x+%2B+3%29\"\r
\n" ); document.write( "\n" ); document.write( "take both sides to be an exponent of 10\r
\n" ); document.write( "\n" ); document.write( "\"10%5E%28log+x%29+=+10%5E%281+-+log%28x+%2B+3%29%29\"
\n" ); document.write( "\"+x+=+10%2F%28x%2B3%29+\"
\n" ); document.write( "\"x%5E2+%2B+x+-+10=0\"\r
\n" ); document.write( "\n" ); document.write( "Just check for extranous values, because there is only one solution to the problem but the quadratic will give you two.
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\n" ); document.write( "third one. Here, it would have been helpful if you had been more clear. is it \"%28e%5E6%29%5Ey\" or \"e%5E%286%5Ey%29\". This is not communitive, meaning these mean different things. I'm going to assume you meant the second one because that is the literal translation of what you said.
\n" ); document.write( "\"e%5E6%5Ey+=+25\"
\n" ); document.write( "Take natural log of both sides
\n" ); document.write( "\"+6%5Ey+=+ln%2825%29+\"
\n" ); document.write( "Take log base 6 of both sides
\n" ); document.write( "\"+y+=+log_6%28ln%2825%29%29\"
\n" ); document.write( "
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