document.write( "Question 111499This question is from textbook
\n" ); document.write( ": Determine how many real roots the equation has (x-4)^2=0\r
\n" ); document.write( "\n" ); document.write( "I know there are 1, which means when i put it in b^2-4ac it equals 0, but i dont know how to get it into that form. \n" ); document.write( "

Algebra.Com's Answer #81391 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"%28x-4%29%5E2=0\"$
\n" ); document.write( " $\"x%5E2+-+8x+%2B+16+=+0\"$
\n" ); document.write( "this is in the form $\"ax%5E2+%2B+bx+%2B+c+=+0\"$
\n" ); document.write( "a = 1
\n" ); document.write( "b = -8
\n" ); document.write( "c = 16
\n" ); document.write( " $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "As long as $\"b%5E2+-+4ac\"$ is a positive number, the roots are real
\n" ); document.write( "If $\"b%5E2+=+4ac\"$ , there is a single real root
\n" ); document.write( " $\"b%5E2+-+4ac+=+%28-8%29%5E2+-+4%2A1%2A16\"$
\n" ); document.write( " $\"b%5E2+-+4ac+=+64+-+64\"$
\n" ); document.write( " $\"b%5E2+-+4ac+=+0\"$
\n" ); document.write( " $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( " $\"x+=+%28-%28-8%29+%2B-+sqrt%280+%29%29%2F%282%2A1%29+\"$
\n" ); document.write( " $\"x+=+8%2F2\"$
\n" ); document.write( " $\"x+=+4\"$ answer \n" ); document.write( "

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