document.write( "Question 1183520: Pls help fast :) \r
\n" );
document.write( "\n" );
document.write( "Gene rented a car for “$30 a day and $.30 a mile.” How far did he drive in 2
\n" );
document.write( "days if his bill was $105? \n" );
document.write( "
Algebra.Com's Answer #813878 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the cost to rent a car is 30 dollars a day plus 30 cents a mile. \n" ); document.write( "his bill was 105 for 2 day rental. \n" ); document.write( "take away 60 dollars for the 2 day to get 45 dollars at 30 cents a mile. \n" ); document.write( "divide 45 by .30 to get 150 miles.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that should be your answer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula is c = 30 * x + .30 * y \n" ); document.write( "x is the number of days. \n" ); document.write( "y is the number of miles.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 2, the formula becomes: \n" ); document.write( "c = 30 * 2 + .30 * y \n" ); document.write( "simplify to get: \n" ); document.write( "c = 60 + .30 * y \n" ); document.write( "subtract 60 from both sides of the equation to get: \n" ); document.write( "c - 60 = .30 * y \n" ); document.write( "when c = 105, the formula becomes: \n" ); document.write( "105 - 60 = .30 * y \n" ); document.write( "simplify to get: \n" ); document.write( "45 = .30 * y \n" ); document.write( "divide both sides of the equation by .30 to get: \n" ); document.write( "45/.30 = y \n" ); document.write( "solve for y to get: \n" ); document.write( "y = 150 \n" ); document.write( " |