document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1183517>Question 1183517</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If f(x)= 3x-5 and g(x)= 2-x², find (f+g)(5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #813873 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=813873\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x) = 3x-5<BR>\n" );
document.write( "g(x) = 2-x^2<BR>\n" );
document.write( "(f+g)(x) = 3x-5 + 2-x^2<BR>\n" );
document.write( "simplify this and arrange in descending order of degree to get:<BR>\n" );
document.write( "(f+g)(x) = -x^2+3x-3<BR>\n" );
document.write( "(f+g)(5) = -5^2+3*5-3 = -25+15-3 = -13.\r<BR>\n" );
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document.write( "to see if this is true, solve for f(5) and g(5) separately and then add them together.\r<BR>\n" );
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document.write( "f(5) = 3*5-5 = 10<BR>\n" );
document.write( "g(5) = 2-5^2 = -23<BR>\n" );
document.write( "f(5) + g(5) = 10-23 = -13.\r<BR>\n" );
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document.write( "the value is the same.<BR>\n" );
document.write( "(f+g)(5) give you the same value as f(5)+g(5).\r<BR>\n" );
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