document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1183482>Question 1183482</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Consider the curve given by the parametric equations:<BR>\n" );
document.write( "x = 3t^2 - 6t<BR>\n" );
document.write( "y = t^4 - 2t^3 - 2t^2 - 2t + 5\r<BR>\n" );
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document.write( "a. There are two sections of this curve that go between the point (−3,0) and (9,8). Set up an integral that expresses the area under the upper of those two sections and evaluate it.\r<BR>\n" );
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document.write( "b. Set up and simplify  the integral that represents the length of the curve from the point (9,8) to the point (24,93).  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #813833 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=813833\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a. The area between the upper curve of the parametric equations <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+3t%5E2+-+6t ALIGN=MIDDLE  ALT=\"x+=+3t%5E2+-+6t\"   DISABLED_style= \"max-width:90%; height:auto;\" >, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+t%5E4+-+2t%5E3+-+2t%5E2+-+2t+%2B+5 ALIGN=MIDDLE  ALT=\"y+=+t%5E4+-+2t%5E3+-+2t%5E2+-+2t+%2B+5\"   DISABLED_style= \"max-width:90%; height:auto;\" > and the x-axis<BR>\n" );
document.write( " (i.e., between the point (−3,0) and (9,8)) is given by \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+6+%2Aint%28%28t%5E5+-+3t%5E4%2B7t+-+5%29%2C+dt%2C+1%2C-1%29+=+56%2F5 ALIGN=MIDDLE  ALT=\"A+=+6+%2Aint%28%28t%5E5+-+3t%5E4%2B7t+-+5%29%2C+dt%2C+1%2C-1%29+=+56%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "b.  The expression for the arc length from  from the point (9,8) to the point (24,93) is given by\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=int%28sqrt%2816t%5E6-48t%5E5%2B4t%5E4%2B32t%5E3+%2B76t%5E2-56t%2B40%29%2C+dt%2C+3%2C4%29 ALIGN=MIDDLE  ALT=\"int%28sqrt%2816t%5E6-48t%5E5%2B4t%5E4%2B32t%5E3+%2B76t%5E2-56t%2B40%29%2C+dt%2C+3%2C4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "If you need the complete details on these answers message me. </SPAN>\n" );
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