document.write( "Question 1183489: Hi
\n" ); document.write( "A store owner has a pound of a mixture of nuts that is 90% peanuts and 10% Brazil nuts by weight. How much weight in Brazil nuts must be added to make the mixture 75% peanuts. \r
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Algebra.Com's Answer #813831 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "As a fraction, the part of the original mixture that is peanuts is \"%28.9%29%2F%281%29\"

\n" ); document.write( "After additional amount x of Brazil nuts is added to the mixture, the fraction that is peanuts is \"%28.9%29%2F%281%2Bx%29\"

\n" ); document.write( "The fraction of the mixture that is peanuts is now 3/4:

\n" ); document.write( "\"%28.9%29%2F%281%2Bx%29+=+3%2F4\"
\n" ); document.write( "\"3x%2B3+=+3.6\"
\n" ); document.write( "\"3x+=+0.6\"
\n" ); document.write( "\"x+=+0.2\"

\n" ); document.write( "ANSWER: 0.2 pounds of Brazil nuts must be added to make the mixture 75% peanuts.

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