document.write( "Question 1183433: A manufacturer has found that if his product is priced at N90/unit then his weekly demand is 50 units, but the demand rises to 60 units per week if the selling price is N70/unit. His weekly fixed cost is N3, 000 and variable cost N20/unit.
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document.write( "Find the level of production which maximizes profit and determine the maximum profit?
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Algebra.Com's Answer #813773 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "A manufacturer has found that if his product is priced at N90/unit then his weekly demand is 50 units, \n" ); document.write( "but the demand rises to 60 units per week if the selling price is N70/unit. His weekly fixed cost is N3, 000 \n" ); document.write( "and variable cost N20/unit. Find the level of production which maximizes profit and determine the maximum profit? \n" ); document.write( "~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Let \"n\" be the number of units produced and sold.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then the total cost function is C(n) = 3000 + 20n.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Now we want to determine the revenue function, and for it, we need to know the unit selling price as the function of production.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The problem tells us that the unit selling price falls N20 from N90 to N70 when production rises 10 units from 50 to 60.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "We assume (as always in such problems), that the unit selling price function p(n) is linear, so it is p(n) = 90 - 2(n-50).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Therefore, the revenue is\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " R(n) = n*p(n) = n*(90-2(n-50)) = 90n -2n^2 + 100n = -2n^ + 190n.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Now the profit is\r\n" ); document.write( "\r\n" ); document.write( " \r\n" ); document.write( " P(n) = R(n) - C(n) = -2n^2 + 190n - 3000 - 20n = -2n^2 + 170n - 3000. (1)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The problem asks about the maximum of the profit, which is the vertex of the quadratic function (1).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The maximum happens at n = \"\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |