document.write( "Question 1183431: Three yam tubers are chosen at random from 15 tubers of which 5 are spoilt. Find the probability that,of the three chosen tubers:
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Algebra.Com's Answer #813767 by ikleyn(53751)\"\" \"About 
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\n" ); document.write( "Three yam tubers are chosen at random from 15 tubers of which 5 are spoilt. Find the probability that, of the three chosen tubers:
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\n" ); document.write( "D. At least one is spoilt.
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document.write( "(A)  In part (A), you chose, actually, 3 tubers from 10 tubers that are not spoilt, among the total of 15 tubers.\r\n" );
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document.write( "     Therefore, you can use any of two formulas to find the probability\r\n" );
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document.write( "         P = \"%2810%2F15%29%2A%289%2F14%29%2A%288%2F13%29\" = \"%282%2F3%29%2A%289%2F14%29%2A%288%2F13%29\" = \"24%2F91\" = 0.2637  (rounded),\r\n" );
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document.write( "     or\r\n" );
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document.write( "         P = \"C%5B10%5D%5E3%2FC%5B15%5D%5E3\" = \"120%2F455\" = \"24%2F91\" = 0.2637  (same as above).\r\n" );
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document.write( "(B)  In part (B), you select, actually, 3 tubers from 5 spoilt tubers, among the total 15 tubers.\r\n" );
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document.write( "     Therefore, you can use any of two formulas to find the probability\r\n" );
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document.write( "         P = \"%285%2F15%29%2A%284%2F14%29%2A%283%2F13%29\" = \"%281%2F3%29%2A%282%2F7%29%2A%283%2F13%29\" = \"2%2F91\" = 0.0219  (rounded),\r\n" );
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document.write( "     or\r\n" );
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document.write( "         P = \"C%5B5%5D%5E3%2FC%5B15%5D%5E3\" = \"10%2F455\" = \"2%2F91\" = 0.0219  (the same value).\r\n" );
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document.write( "(C)  \"Exactly one is spoilt\" means one is spoilt of the 3 selected among the total 15, and 2 are not.\r\n" );
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document.write( "     Therefore, you can use this formula to find the probability\r\n" );
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document.write( "         P = \"%28C%5B5%5D%5E1%2AC%5B10%5D%5E2%29%2FC%5B15%5D%5E3\" = \"%285%2A45%29%2F455\" = \"45%2F91\" = 0.4945.    (rounded)\r\n" );
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document.write( "(D)  It is the complement probability to the value found in (A)\r\n" );
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document.write( "         P = 1 - 0.2637 = 0.7363   (rounded).\r\n" );
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