document.write( "Question 1182608: Terri Vogel, an amateur motorcycle racer, averages per 129.95 seconds per 2.5 mile lap (in a 7 lap race) with a standard deviation of 2.28 seconds.
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document.write( "The distribution of her race times is normally distributed.
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document.write( "We are interested in one of her randomly selected laps.
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document.write( "Let X be the number of seconds for a randomly selected lap.
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document.write( "Round to 4 decimals.
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document.write( "a. What is the distribution of X?
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document.write( " =129.95 over 2.28\r
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document.write( "b. Find the proportion of her laps that are completed between 126.17 and 127.91 seconds.\r
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document.write( "c. Find the fastest 4% of laps are under ______ seconds.\r
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document.write( "d. The middle 40% of her laps are from ______ seconds to _______ seconds.
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Algebra.Com's Answer #813766 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! X~N(129.95, 5.1984) units seconds, seconds^2 (use the variance) \n" ); document.write( "z=(x-mean)/sd \n" ); document.write( "z=-3.78/2.28=-1.658 \n" ); document.write( "z=(-2.04/2.28)=-0.895 \n" ); document.write( "that probability is 0.1367 \n" ); document.write( "can check with 2ndVARS2(normalcdf(126.17,127.91,129.95,2.28)ENTER which is unrounded and 0.1368. I would use the first, unless the course requires no rounding of the z-value until the end.\r \n" ); document.write( "\n" ); document.write( "The fastest 4% of laps: z(0.04), since want the shortest time, z=-1.7506 \n" ); document.write( "-1.7506=(x-129.95)/2.28 \n" ); document.write( "=125.96 seconds \n" ); document.write( "- \n" ); document.write( "This requires z (0.3) and z(0.7), which are -0.5244 and +0.5244 respectively \n" ); document.write( "-0.5244=(x-129.95)/2.28 \n" ); document.write( "x=128.75 sec \n" ); document.write( "and \n" ); document.write( "x=131.15 sec \n" ); document.write( "If this is checked, it is about 0.4013 of the laps, the discrepancy's being that the multiplying z by -0.5244 gives 1.1956 seconds, which was rounded upward to 1.20 seconds. \n" ); document.write( " |