document.write( "Question 1183424: Let x◦ be the measurement of an angle. The ratio of the measurement of the complement of the angle to the measurement of the supplement of the angle is 1:3. The measurement of the complement of the angle and the measurement of the
\n" ); document.write( "supplement of the angle have a sum of 180◦ . Find x. \n" ); document.write( "

Algebra.Com's Answer #813745 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Let x◦ be the measurement of an angle.
\n" ); document.write( "The ratio of the measurement of the complement of the angle to the measurement of the supplement of the angle is 1:3.
\n" ); document.write( " $\"%28%2890-x%29%29%2F%28%28180-x%29%29+=+1%2F3\"$
\n" ); document.write( "cross multiplyL
\n" ); document.write( "3(90-x) = 180 - x
\n" ); document.write( "270 - 3x = 180 - x
\n" ); document.write( "270 - 180 = -x + 3x
\n" ); document.write( "90 = 2x
\n" ); document.write( "x = 45
\n" ); document.write( ":
\n" ); document.write( "The measurement of the complement of the angle and the measurement of the
\n" ); document.write( "supplement of the angle have a sum of 180◦ . Find x.
\n" ); document.write( ":
\n" ); document.write( "(90-x) + (180-x) = 180
\n" ); document.write( "90 - x + 180 - x - 180 = 0
\n" ); document.write( "90 = 2x
\n" ); document.write( "x = 45 \n" ); document.write( "

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