document.write( "Question 111583: The problem is- Solve the system by using matrix elimination:
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document.write( "3a-2b=5
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document.write( "2a+7b=9\r
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document.write( "I know that its suppose to end up looking like this:
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document.write( "1 0 a
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document.write( "0 1 b
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document.write( "but I dont know how to solve this because of the 3a and the 2a. \n" );
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Algebra.Com's Answer #81374 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Write the coefficients and the right side constants in an augmented matrix:\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply Row 1 by \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " Add -2*Row 1 to Row 2 to get the new Row 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply Row 2 by \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add 2/3*Row 2 to Row 1 to get the new row 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The matrix is now in reduced row echelon form\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you need more help with row reduction, check out the Linear Algebra Toolkit \n" ); document.write( " \n" ); document.write( " |