document.write( "Question 1183409: The probability that a management trainee will remain with a company is 0.6.The
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document.write( "probability of an employee earning more than Rs 10000 per year is 0.5. The
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document.write( "probability that an employee is a management trainee who remained with the
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document.write( "company or who earns more than Rs. 10000 per year is 0.70. What is the probability
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document.write( "that an employee earns more than Rs a 10000; per year given that he is a
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document.write( "management trainee who stayed with the company? \n" );
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Algebra.Com's Answer #813717 by ikleyn(52817)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "Use this probability identity\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " P(A U B) = P(A) + P(B) - P(A and B).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "In your case it becomes\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 0.7 = 0.6 + 0.5 - P(A and B)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "and gives\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " P(A and B) = 0.6 + 0.5 - 0.7 = 0.4. ANSWER\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved and explained.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |