document.write( "Question 1183388: An open lid tank to be made by concrete has width 50𝑐𝑚, inside capacity of 4000 𝑚3
\n" ); document.write( "and square base. Find the inner dimension of the tank with the minimum volume of
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Algebra.Com's Answer #813692 by robertb(5830)\"\" \"About 
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The thickness of the open-lid tank is 50 cm = \"%281%2F2%29+m\". Let the interior square base have a side of length \"+x+\" meters. \r
\n" ); document.write( "\n" ); document.write( "Also let the inner height be \"y+\" m.
\n" ); document.write( "This then gives \r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Ay+=+4000\"\r
\n" ); document.write( "\n" ); document.write( "since it is given that the inside capacity is \"4000+m%5E3\".\r
\n" ); document.write( "\n" ); document.write( "For the exterior of the tank, the square base has a side of length
\n" ); document.write( "\"+x+%2B+2%2A%281%2F2%29+=+x%2B1\" meters, and a height of \"y+%2B+1%2F2\" meters.\r
\n" ); document.write( "\n" ); document.write( "The external volume is then \r
\n" ); document.write( "\n" ); document.write( "\"V+=+%28x%2B1%29%5E2%2A%28y%2B1%2F2%29+=+%28x%2B1%29%5E2%2A%28+4000%2Fx%5E2+%2B1%2F2%29\", after substituting for \"y\" from the previous equation.\r
\n" ); document.write( "\n" ); document.write( "==> , \r
\n" ); document.write( "\n" ); document.write( "after simplifying the expression on the right side.\r
\n" ); document.write( "\n" ); document.write( "Setting \"dV%2Fdx+=+%28%28x%2B1%29%2A%28x%5E3+-+8000%29%29%2Fx%5E3+=+0\", we get \"x+=+20+m\".\r
\n" ); document.write( "\n" ); document.write( "We cannot accept \"x+=+-1\" since the domain of V is \"x+%3E+0\".\r
\n" ); document.write( "\n" ); document.write( "Now if \"x+%3C+20\", \"dV%2Fdx+%3C+0+\", and \r
\n" ); document.write( "\n" ); document.write( "when \"x+%3E+20\", \"dV%2Fdx+%3E+0+\", so by the the 1st derivative test, \r
\n" ); document.write( "\n" ); document.write( "there is a local minimum at \"x+=+20\". Since it is the only critical \r
\n" ); document.write( "\n" ); document.write( "point in the domain (0, \"infinity\"), the minimum at \"x+=+20\" is also\r
\n" ); document.write( "\n" ); document.write( "absolute minimum. \r
\n" ); document.write( "\n" ); document.write( "Therefore the inner dimensions of the tank are 20 m x 20 m x 10m. (The height is \r
\n" ); document.write( "\n" ); document.write( "\"y+=+4000%2Fx%5E2+=+4000%2F20%5E2+=+10+m\".)\r
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