document.write( "Question 1183389: An open lid tank to be made by concrete has width 50𝑐𝑚, inside capacity of 4000 𝑚3
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document.write( "and square base. Find the inner dimension of the tank with the minimum volume of
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document.write( "concrete \n" );
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Algebra.Com's Answer #813688 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Solved a few days ago. The response is copied below. \n" ); document.write( "----------------------------------------------------------------------- \n" ); document.write( " \n" ); document.write( "Let x be the inside length in meters of a side of the square base; let h be the height/depth of the tank. \n" ); document.write( "Then the volume of the tank is \n" ); document.write( " \n" ); document.write( "Since the thickness of the concrete is 50cm = 0.5m, the square base has dimensions (x+1)(x+1)(0.5). \n" ); document.write( "The four sides of the tank can be viewed as four congruent rectangular solids each with dimensions (x+0.5)(h)(0.5). \n" ); document.write( "So the total volume of the tank is \n" ); document.write( " \n" ); document.write( "Solve [1] for h in terms of x and substitute in the volume formula to get the volume in terms of the single variable x. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Differentiate and set the derivative equal to zero to find the length of the side of the square base that minimizes the volume of concrete. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Clearly the negative solution makes no sense in the problem. So \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWER: The volume of concrete to make the tank is minimized when the side length of the square base is 20m \n" ); document.write( " |