document.write( "Question 1179000: A medical researcher wants to determine whether a drug changes the body's temperature. Seven test subjects are randomly selected, and the body temperature (in degrees Fahrenheit) of each is measured. The subjects are then given the drug and after 20 minutes, the body temperature of each is measured again. The results are listed below. At α=0.05, is there enough evidence to conclude that the drug reduces the body's temperature? \r
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\n" ); document.write( "\n" ); document.write( "Subject
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\n" ); document.write( "\n" ); document.write( "1
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\n" ); document.write( "\n" ); document.write( "2
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\n" ); document.write( "\n" ); document.write( "3
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\n" ); document.write( "\n" ); document.write( "4
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\n" ); document.write( "\n" ); document.write( "5
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\n" ); document.write( "\n" ); document.write( "6
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\n" ); document.write( "\n" ); document.write( "7 \r
\n" ); document.write( "\n" ); document.write( "Initial Temperature
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\n" ); document.write( "\n" ); document.write( "103.4
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\n" ); document.write( "\n" ); document.write( "102.5
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\n" ); document.write( "\n" ); document.write( "101.1
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\n" ); document.write( "\n" ); document.write( "103.4
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\n" ); document.write( "\n" ); document.write( "102.9
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\n" ); document.write( "\n" ); document.write( "100.2
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\n" ); document.write( "\n" ); document.write( "100.9 \r
\n" ); document.write( "\n" ); document.write( "Second temperature
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\n" ); document.write( "\n" ); document.write( "99.2
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\n" ); document.write( "\n" ); document.write( "98.4
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\n" ); document.write( "\n" ); document.write( "98.2
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\n" ); document.write( "\n" ); document.write( "99
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\n" ); document.write( "\n" ); document.write( "98.6
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\n" ); document.write( "\n" ); document.write( "99.7
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\n" ); document.write( "\n" ); document.write( "97.8 \r
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\n" ); document.write( "\n" ); document.write( " Conditions: \r
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\n" ); document.write( "\n" ); document.write( " Significance Level:\r
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\n" ); document.write( "\n" ); document.write( "Conclusion:
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Algebra.Com's Answer #813642 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
The following are the values of \"d%5Bi%5D\" = temp after - temp before:\r
\n" ); document.write( "\n" ); document.write( "-4.2, -4.1, -2.9, -4.4, -4.3, -0.5, -3.1.\r
\n" ); document.write( "\n" ); document.write( "==> \"d%5Bm%5D+=+-23.5%2F7+=+-3.357\" and to 3 d.p.\r
\n" ); document.write( "\n" ); document.write( "Now \r
\n" ); document.write( "\n" ); document.write( "\"H%5B0%5D%3A++d+=+0\" and \"H%5Ba%5D%3A+d%3C+0\", with 5% significance level.\r
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\n" ); document.write( "\n" ); document.write( "Using the test statistic , one obtains \"t+=+%28sqrt%287%29%2A-3.357%29%2F1.395+=+-6.367\".\r
\n" ); document.write( "\n" ); document.write( "The critical t-value is given by \"t%5B0.025%5D+=+-2.447\" using https://stattrek.com/online-calculator/t-distribution.aspx.\r
\n" ); document.write( "\n" ); document.write( "Since \"t+=+-6.367+%3C+-2.447+=+t%5B0.025%5D\", we reject the null hypothesis and conclude that the drug reduces the body'stemperature.
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